Optimal. Leaf size=86 \[ b \sin (2 a) \text{CosIntegral}(2 b x) \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}+b \cos (2 a) \text{Si}(2 b x) \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}-\frac{\left (c \sin ^3(a+b x)\right )^{2/3}}{x} \]
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Rubi [A] time = 0.183908, antiderivative size = 86, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {6720, 3313, 12, 3303, 3299, 3302} \[ b \sin (2 a) \text{CosIntegral}(2 b x) \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}+b \cos (2 a) \text{Si}(2 b x) \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}-\frac{\left (c \sin ^3(a+b x)\right )^{2/3}}{x} \]
Antiderivative was successfully verified.
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Rule 6720
Rule 3313
Rule 12
Rule 3303
Rule 3299
Rule 3302
Rubi steps
\begin{align*} \int \frac{\left (c \sin ^3(a+b x)\right )^{2/3}}{x^2} \, dx &=\left (\csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}\right ) \int \frac{\sin ^2(a+b x)}{x^2} \, dx\\ &=-\frac{\left (c \sin ^3(a+b x)\right )^{2/3}}{x}+\left (2 b \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}\right ) \int \frac{\sin (2 a+2 b x)}{2 x} \, dx\\ &=-\frac{\left (c \sin ^3(a+b x)\right )^{2/3}}{x}+\left (b \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}\right ) \int \frac{\sin (2 a+2 b x)}{x} \, dx\\ &=-\frac{\left (c \sin ^3(a+b x)\right )^{2/3}}{x}+\left (b \cos (2 a) \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3}\right ) \int \frac{\sin (2 b x)}{x} \, dx+\left (b \csc ^2(a+b x) \sin (2 a) \left (c \sin ^3(a+b x)\right )^{2/3}\right ) \int \frac{\cos (2 b x)}{x} \, dx\\ &=-\frac{\left (c \sin ^3(a+b x)\right )^{2/3}}{x}+b \text{Ci}(2 b x) \csc ^2(a+b x) \sin (2 a) \left (c \sin ^3(a+b x)\right )^{2/3}+b \cos (2 a) \csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3} \text{Si}(2 b x)\\ \end{align*}
Mathematica [A] time = 0.148407, size = 65, normalized size = 0.76 \[ \frac{\csc ^2(a+b x) \left (c \sin ^3(a+b x)\right )^{2/3} (2 b x \sin (2 a) \text{CosIntegral}(2 b x)+2 b x \cos (2 a) \text{Si}(2 b x)+\cos (2 (a+b x))-1)}{2 x} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.089, size = 211, normalized size = 2.5 \begin{align*}{\frac{{\frac{i}{4}}b}{ \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) ^{2}} \left ( ic \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) ^{3}{{\rm e}^{-3\,i \left ( bx+a \right ) }} \right ) ^{{\frac{2}{3}}} \left ({\frac{i}{bx}}+2\,{{\rm e}^{2\,ibx}}{\it Ei} \left ( 1,2\,ibx \right ) \right ) }+{\frac{{\frac{i}{4}}b}{ \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) ^{2}} \left ( ic \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) ^{3}{{\rm e}^{-3\,i \left ( bx+a \right ) }} \right ) ^{{\frac{2}{3}}} \left ({\frac{i{{\rm e}^{4\,i \left ( bx+a \right ) }}}{bx}}-2\,{\it Ei} \left ( 1,-2\,ibx \right ){{\rm e}^{2\,i \left ( bx+2\,a \right ) }} \right ) }+{\frac{{{\rm e}^{2\,i \left ( bx+a \right ) }}}{2\, \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) ^{2}x} \left ( ic \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) ^{3}{{\rm e}^{-3\,i \left ( bx+a \right ) }} \right ) ^{{\frac{2}{3}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] time = 1.64815, size = 378, normalized size = 4.4 \begin{align*} \frac{{\left (64 \,{\left ({\left (-i \, \sqrt{3} + 1\right )} E_{2}\left (2 i \, b x\right ) +{\left (i \, \sqrt{3} + 1\right )} E_{2}\left (-2 i \, b x\right )\right )} \cos \left (2 \, a\right )^{3} -{\left ({\left (64 \, \sqrt{3} + 64 i\right )} E_{2}\left (2 i \, b x\right ) +{\left (64 \, \sqrt{3} - 64 i\right )} E_{2}\left (-2 i \, b x\right )\right )} \sin \left (2 \, a\right )^{3} + 64 \,{\left ({\left ({\left (-i \, \sqrt{3} + 1\right )} E_{2}\left (2 i \, b x\right ) +{\left (i \, \sqrt{3} + 1\right )} E_{2}\left (-2 i \, b x\right )\right )} \cos \left (2 \, a\right ) - 4\right )} \sin \left (2 \, a\right )^{2} + 64 \,{\left ({\left (i \, \sqrt{3} + 1\right )} E_{2}\left (2 i \, b x\right ) +{\left (-i \, \sqrt{3} + 1\right )} E_{2}\left (-2 i \, b x\right )\right )} \cos \left (2 \, a\right ) - 256 \, \cos \left (2 \, a\right )^{2} -{\left ({\left ({\left (64 \, \sqrt{3} + 64 i\right )} E_{2}\left (2 i \, b x\right ) +{\left (64 \, \sqrt{3} - 64 i\right )} E_{2}\left (-2 i \, b x\right )\right )} \cos \left (2 \, a\right )^{2} -{\left (64 \, \sqrt{3} - 64 i\right )} E_{2}\left (2 i \, b x\right ) -{\left (64 \, \sqrt{3} + 64 i\right )} E_{2}\left (-2 i \, b x\right )\right )} \sin \left (2 \, a\right )\right )} b c^{\frac{2}{3}}}{1024 \,{\left (a \cos \left (2 \, a\right )^{2} + a \sin \left (2 \, a\right )^{2} -{\left (b x + a\right )}{\left (\cos \left (2 \, a\right )^{2} + \sin \left (2 \, a\right )^{2}\right )}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.79522, size = 332, normalized size = 3.86 \begin{align*} -\frac{4^{\frac{2}{3}}{\left (2 \cdot 4^{\frac{1}{3}} b x \cos \left (2 \, a\right ) \operatorname{Si}\left (2 \, b x\right ) + 2 \cdot 4^{\frac{1}{3}} \cos \left (b x + a\right )^{2} +{\left (4^{\frac{1}{3}} b x \operatorname{Ci}\left (2 \, b x\right ) + 4^{\frac{1}{3}} b x \operatorname{Ci}\left (-2 \, b x\right )\right )} \sin \left (2 \, a\right ) - 2 \cdot 4^{\frac{1}{3}}\right )} \left (-{\left (c \cos \left (b x + a\right )^{2} - c\right )} \sin \left (b x + a\right )\right )^{\frac{2}{3}}}{8 \,{\left (x \cos \left (b x + a\right )^{2} - x\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \sin ^{3}{\left (a + b x \right )}\right )^{\frac{2}{3}}}{x^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \sin \left (b x + a\right )^{3}\right )^{\frac{2}{3}}}{x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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